如何将字符串转换为地址？

cl_mark

怎样将字符串192.168.1.233:21转换为ace_inet_addr的对象？说详细点，谢谢拉

earthdog

ACE_INET_Addr有一个构造函数满足你的要求：

/**
   * Initializes an ACE_INET_Addr from the <address>, which can be
   * "ip-number:port-number" (e.g., "tango.cs.wustl.edu:1234" or
   * "128.252.166.57:1234").  If there is no ':' in the <address> it
   * is assumed to be a port number, with the IP address being
   * INADDR_ANY.
   */
  explicit ACE_INET_Addr (const char address[],
                          int address_family = AF_UNSPEC);



调用方式就很简单了三，
ACE_INET_Addr addr("192.168.1.233:21", AF_INET);


同时，还有一个set()函数也可以做同样的操作：

  /**
   * Initializes an ACE_INET_Addr from the @a addr, which can be
   * "ip-number:port-number" (e.g., "tango.cs.wustl.edu:1234" or
   * "128.252.166.57:1234").  If there is no ':' in the <address> it
   * is assumed to be a port number, with the IP address being
   * INADDR_ANY.
   */
  int set (const char addr[], int address_family = AF_UNSPEC);

调用方式如下：
ACE_INET_Addr addr;
addr.set("192.168.1.233:21", AF_INET);

[ 本帖最后由 earthdog 于 2008-4-22 17:32 编辑 ]