使用内存池时，怎么调用对象的虚构函数？

peakzhang

2. typedef ACE_Allocator_Adapter<ACE_Malloc<ACE_LOCAL_MEMORY_POOL,ACE_SYNCH_MUTEX> > Malloc_Allocator;
3. Malloc_Allocator gAlloc;
4. class aaa
5. {
6. public:
7. aaa(){printf("aaa\n");}
8. ~aaa(){printf("~aaa() \n");}
9. int x;
10. };
11. void *p = gAlloc.malloc(sizeof(aaa));
12. aaa *poa = new (p) aaa(); //调用类aaa的构造函数

复制代码

。。。
释放：
gAlloc.free(poa);  //不能调用到poa的虚构函数
poa = NULL;
请问我释放空间用aAlloc.free(poa);还是delete poa;?

peakzhang

应该按自己调用析构的：

#include <iostream>
class bbbb
{
public:
    bbbb(void){std::cout<<"bbbb(void)\n";}
    ~bbbb(void){std::cout<<"~bbbb(void)\n";}
};

class aaaa :public bbbb
{
public:
    aaaa(void):i(0){std::cout<<"aaaa(void)\n";}
    ~aaaa(void){std::cout<<"~aaaa(void)\n";}
protected:
private:
    int i;
};


int

main (int argc, char *argv[])

{

    int *t =new int[100];

    aaaa *b=new(t) aaaa;

    b->~aaaa();

    delete[] t;

    return 0;

}


输出如下：

bbbb(void)

aaaa(void)

~aaaa(void)

~bbbb(void)