使用内存池时，怎么调用对象的虚构函数？
typedef ACE_Allocator_Adapter<ACE_Malloc<ACE_LOCAL_MEMORY_POOL,ACE_SYNCH_MUTEX> > Malloc_Allocator;
Malloc_Allocator gAlloc;
class aaa
{
public:
aaa(){printf("aaa\n");}
~aaa(){printf("~aaa() \n");}
int x;
};
void *p = gAlloc.malloc(sizeof(aaa));
aaa *poa = new (p) aaa(); //调用类aaa的构造函数
。。。
释放：
gAlloc.free(poa);//不能调用到poa的虚构函数
poa = NULL;
请问我释放空间用aAlloc.free(poa);还是delete poa;? 应该按自己调用析构的：
#include <iostream>
class bbbb
{
public:
bbbb(void){std::cout<<"bbbb(void)\n";}
~bbbb(void){std::cout<<"~bbbb(void)\n";}
};
class aaaa :public bbbb
{
public:
aaaa(void):i(0){std::cout<<"aaaa(void)\n";}
~aaaa(void){std::cout<<"~aaaa(void)\n";}
protected:
private:
int i;
};
int
main (int argc, char *argv[])
{
int *t =new int;
aaaa *b=new(t) aaaa;
b->~aaaa();
delete[] t;
return 0;
}
输出如下：
bbbb(void)
aaaa(void)
~aaaa(void)
~bbbb(void)
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